What is the derivative of (3x+4^2) ?

The derivative of (3x+4^2) is 6(3x+4)

What is the first derivative of (3x+4^2) ?

The first derivative of (3x+4^2) is 6(3x+4)

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\frac{d}{d x} ((3 x + 4)^{2})

6 (3 x + 4)

Solution steps

\frac{d}{d x} ((3 x + 4)^{2})

Apply the chain rule:

2 (3 x + 4) \frac{d}{d x} (3 x + 4)

= 2 (3 x + 4) \frac{d}{d x} (3 x + 4)

\frac{d}{d x} (3 x + 4) = 3

= 2 (3 x + 4) \cdot 3

Simplify

= 6 (3 x + 4)

x \to - 2 lim (- 2)

\int \frac{3 y}{( 2 + 3 y ^{2} ) ^{3}} d y

\frac{d}{d x} (cos^{2} (3 x + 1) - sin^{2} (3 x + 1))

\int 1 + sin (x) d x

f (x) = 2^{x + 1}

What is the derivative of (3x+4^2) ?
The derivative of (3x+4^2) is 6(3x+4)
What is the first derivative of (3x+4^2) ?
The first derivative of (3x+4^2) is 6(3x+4)