What is the derivative of f(x)=sqrt(x)-8\sqrt[3]{x} ?

The derivative of f(x)=sqrt(x)-8\sqrt[3]{x} is 1/(2sqrt(x))-8/(3x^{2/3)}

What is the first derivative of f(x)=sqrt(x)-8\sqrt[3]{x} ?

The first derivative of f(x)=sqrt(x)-8\sqrt[3]{x} is 1/(2sqrt(x))-8/(3x^{2/3)}

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derivative of

\frac{1}{2 x} - \frac{8}{3 x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} - \frac{8}{3 x ^{\frac{2}{3}}}

t \to 1 lim (sin (- 5 π t))

\int_{1}^{5} \frac{x}{5 - x} d x

\frac{9}{4} t^{2} e^{2 t} e^{3 t}

t^{2} (\frac{d y}{d t}) + y^{2} = t y

\frac{d}{d x} (x tan (2 x) + 7)

What is the derivative of f(x)=sqrt(x)-8\sqrt[3]{x} ?
The derivative of f(x)=sqrt(x)-8\sqrt[3]{x} is 1/(2sqrt(x))-8/(3x^{2/3)}
What is the first derivative of f(x)=sqrt(x)-8\sqrt[3]{x} ?
The first derivative of f(x)=sqrt(x)-8\sqrt[3]{x} is 1/(2sqrt(x))-8/(3x^{2/3)}