What is the integral of 1/(sqrt(x)*\sqrt{1-x)} ?

The integral of 1/(sqrt(x)*\sqrt{1-x)} is 2arcsin(sqrt(x))+C

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integral of 1/(sqrt(x)*\sqrt{1-x)}

\int \frac{1}{x \cdot 1 - x} d x

2 arcsin (x) + C

Solution steps

\int \frac{1}{x 1 - x} d x

Apply u-substitution

: \int \frac{2}{1 - u ^{2}} d u

= \int \frac{2}{1 - u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{1 - u ^{2}} d u

Use the common integral:

\int \frac{1}{1 - u ^{2}} d u = arcsin (u)

= 2 arcsin (u)

Substitute back

u = x

= 2 arcsin (x)

Add a constant to the solution

= 2 arcsin (x) + C

\frac{1}{( x - 1 )}

sin (x), \frac{π}{4}

y^{^{''}} + 6 y^{^{'}} + 8 y = 4 sin (2 t)

\int_{1}^{3} x - 1 d x

\frac{d y}{d x} = \frac{e ^{x - y}}{1 + e ^{x}}

What is the integral of 1/(sqrt(x)*\sqrt{1-x)} ?
The integral of 1/(sqrt(x)*\sqrt{1-x)} is 2arcsin(sqrt(x))+C