What is laplacetransform sin(2(t-pi/2)) ?

The answer to laplacetransform sin(2(t-pi/2)) is -2/(s^2+4)

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laplacetransform sin(2(t-pi/2))

laplace transform

sin (2 (t - \frac{π}{2}))

- \frac{2}{s ^{2} + 4}

Solution steps

L {sin (2 (t - \frac{π}{2}))}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (2 (t - \frac{π}{2}))} = \frac{s sin ( - π ) + 2 cos ( - π )}{s ^{2} + 2 ^{2}}

= \frac{s sin ( - π ) + 2 cos ( - π )}{s ^{2} + 2 ^{2}}

= - \frac{2}{s ^{2} + 4}

x^{2} - 4 x, x - 4

\frac{\partial}{\partial y} (2 x^{2} - 5 y^{2})

y^{^{''}} + 4 y = - 16 sin (2 t)

4 x^{2} (\frac{d y}{d x}) = (\frac{d y}{d x}) + 6 x e^{- y}

x \to \infty lim (4 - 5 x)

What is laplacetransform sin(2(t-pi/2)) ?
The answer to laplacetransform sin(2(t-pi/2)) is -2/(s^2+4)