What is the sum from n=1 to infinity}((-1)^{3n of)/n ?

The sum from n=1 to infinity}((-1)^{3n of)/n is converges

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sum from n=1 to infinity}((-1)^{3n of)/n

n = 1 \sum \infty \frac{( - 1 ) ^{3 n}}{n}

converges

Solution steps

n = 1 \sum \infty \frac{( - 1 ) ^{3 n}}{n}

Apply Alternating Series Test:

converges

= converges

f (x) = \frac{6 x}{6 x ^{2} + 5}

\frac{\partial}{\partial x} (sin (π (6 x - 5 y)))

x + \frac{sin ( y )}{cos ( x )} y^{^{'}} = 0

\frac{e ^{x} + e ^{- x}}{6}

f (x) = \frac{3}{( x ^{2} - 5 x ) ^{2}}

What is the sum from n=1 to infinity}((-1)^{3n of)/n ?
The sum from n=1 to infinity}((-1)^{3n of)/n is converges