What is (\partial)/(\partial x)(((1x,3y,4z))*(1,2,3)) ?

The answer to (\partial)/(\partial x)(((1x,3y,4z))*(1,2,3)) is (1,2,3)(1,3y,4z*1)

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(\partial)/(\partial x)(((1x,3y,4z))*(1,2,3))

\frac{\partial}{\partial x} (((1 x, 3 y, 4 z)) \cdot (1, 2, 3))

(1, 2, 3) (1, 3 y, 4 z \cdot 1)

Solution steps

\frac{\partial}{\partial x} (((1 \cdot x, 3 y, 4 z)) (1, 2, 3))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (1, 2, 3) \frac{\partial}{\partial x} (1 \cdot x, 3 y, 4 z)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (1, 2, 3) (1, 3 y, 4 z \frac{\partial}{\partial x} (x))

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= (1, 2, 3) (1, 3 y, 4 z \cdot 1)

\int sin^{3} (x co) s^{12} x d x

\frac{d}{d x} (arcsin (2^{x}))

y^{^{''}} - 4 y^{^{'}} + 4 y = 1

\int_{0}^{\infty} e^{- s t} d t

y = (\frac{( 3 x ^{2} )}{2 x + 4})^{3}

What is (\partial)/(\partial x)(((1x,3y,4z))*(1,2,3)) ?
The answer to (\partial)/(\partial x)(((1x,3y,4z))*(1,2,3)) is (1,2,3)(1,3y,4z*1)