What is the derivative of (x^2-5)(x+7) ?

The derivative of (x^2-5)(x+7) is 3x^2+14x-5

What is the first derivative of (x^2-5)(x+7) ?

The first derivative of (x^2-5)(x+7) is 3x^2+14x-5

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derivative of

(x^{2} - 5) (x + 7)

3 x^{2} + 14 x - 5

Solution steps

\frac{d}{d x} ((x^{2} - 5) (x + 7))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2} - 5, g = x + 7

= \frac{d}{d x} (x^{2} - 5) (x + 7) + \frac{d}{d x} (x + 7) (x^{2} - 5)

\frac{d}{d x} (x^{2} - 5) = 2 x

\frac{d}{d x} (x + 7) = 1

= 2 x (x + 7) + 1 \cdot (x^{2} - 5)

Simplify

2 x (x + 7) + 1 \cdot (x^{2} - 5) : 3 x^{2} + 14 x - 5

= 3 x^{2} + 14 x - 5

\int sin (11 x) d x

\int_{0}^{2} x^{2} - 4 d x

\frac{\partial}{\partial y} (3 z)

\frac{d}{d x} (\frac{2 sin ( x )}{2 + cos ( x )})

\frac{x ^{2} + 2 x}{4 - 5 x}

What is the derivative of (x^2-5)(x+7) ?
The derivative of (x^2-5)(x+7) is 3x^2+14x-5
What is the first derivative of (x^2-5)(x+7) ?
The first derivative of (x^2-5)(x+7) is 3x^2+14x-5