What is the derivative of (x-1^4) ?

The derivative of (x-1^4) is 4(x-1)^3

What is the first derivative of (x-1^4) ?

The first derivative of (x-1^4) is 4(x-1)^3

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\frac{d}{d x} ((x - 1)^{4})

4 (x - 1)^{3}

Solution steps

\frac{d}{d x} ((x - 1)^{4})

Apply the chain rule:

4 (x - 1)^{3} \frac{d}{d x} (x - 1)

= 4 (x - 1)^{3} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 4 (x - 1)^{3} \cdot 1

Simplify

= 4 (x - 1)^{3}

\frac{d}{d x} (\frac{x}{x ^{2}})

\int 144 - x^{2} d x

x \to - 1 lim (x^{3} + 2 x^{2} - 3 x - 4)

\frac{d y}{d x} = (x y)^{2}

x^{(2)} sin (x)

What is the derivative of (x-1^4) ?
The derivative of (x-1^4) is 4(x-1)^3
What is the first derivative of (x-1^4) ?
The first derivative of (x-1^4) is 4(x-1)^3