What is the derivative of f(x)=sin(tan(9x)) ?

The derivative of f(x)=sin(tan(9x)) is cos(tan(9x))sec^2(9x)*9

What is the first derivative of f(x)=sin(tan(9x)) ?

The first derivative of f(x)=sin(tan(9x)) is cos(tan(9x))sec^2(9x)*9

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derivative of

f (x) = sin (tan (9 x))

cos (tan (9 x)) sec^{2} (9 x) \cdot 9

Solution steps

\frac{d}{d x} (sin (tan (9 x)))

Apply the chain rule:

cos (tan (9 x)) \frac{d}{d x} (tan (9 x))

= cos (tan (9 x)) \frac{d}{d x} (tan (9 x))

\frac{d}{d x} (tan (9 x)) = sec^{2} (9 x) \cdot 9

= cos (tan (9 x)) sec^{2} (9 x) \cdot 9

3 e^{- 2 t}

\frac{x}{( x - 1 ) ^{2}}

\int \frac{x ^{2}}{5 x ^{3} + 2} d x

(x + 1) y^{^{'}} = x y

\frac{d}{d x} (cos (x) + cos (2 x))

What is the derivative of f(x)=sin(tan(9x)) ?
The derivative of f(x)=sin(tan(9x)) is cos(tan(9x))sec^2(9x)*9
What is the first derivative of f(x)=sin(tan(9x)) ?
The first derivative of f(x)=sin(tan(9x)) is cos(tan(9x))sec^2(9x)*9