en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+1)y^'=xy

Solution

(x + 1) y^{^{'}} = x y

Solution

y = \frac{e ^{x + 1 + c_{1}}}{x + 1}

Solution steps

(x + 1) y^{'} (x) = x y

Solve separable ODE:

y = \frac{e ^{x + 1 + c_{1}}}{x + 1}

y = \frac{e ^{x + 1 + c_{1}}}{x + 1}

Popular Examples

derivative of cos(x+cos(2x))

\frac{d}{d x} (cos (x) + cos (2 x))

area f(x)=x^2-2x+1,(1,4)area

f (x) = x^{2} - 2 x + 1, (1, 4)

integral of ((2r+1))/((r^2-3r+2))

\int \frac{( 2 r + 1 )}{( r ^{2} - 3 r + 2 )} d r

x d y - y d x = 0

tangent of (-2x)/((x^2+1))tangent of

\frac{- 2 x}{( x ^{2} + 1 )}

Frequently Asked Questions (FAQ)

What is the solution for (x+1)y^'=xy ?
The solution for (x+1)y^'=xy is y=(e^{x+1+c_{1}})/(x+1)