What is the derivative of (x^2-3x)/(t^2+8) ?

The derivative of (x^2-3x)/(t^2+8) is (2x-3)/(t^2+8)

What is the first derivative of (x^2-3x)/(t^2+8) ?

The first derivative of (x^2-3x)/(t^2+8) is (2x-3)/(t^2+8)

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derivative of

\frac{x ^{2} - 3 x}{t ^{2} + 8}

\frac{2 x - 3}{t ^{2} + 8}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 3 x}{t ^{2} + 8})

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{t ^{2} + 8} \frac{d}{d x} (x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{t ^{2} + 8} (\frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= \frac{1}{t ^{2} + 8} (2 x - 3)

Simplify

\frac{1}{t ^{2} + 8} (2 x - 3) : \frac{2 x - 3}{t ^{2} + 8}

= \frac{2 x - 3}{t ^{2} + 8}

\int \frac{y + 1}{2 y} d y

f (x) = (3 x + 1), at a = 1

f (x) = 4 x - \frac{8}{x}

x \to 1 lim (\frac{7}{1 - x})

\frac{\partial}{\partial x} (y - e^{- 2 x^{2} y})

What is the derivative of (x^2-3x)/(t^2+8) ?
The derivative of (x^2-3x)/(t^2+8) is (2x-3)/(t^2+8)
What is the first derivative of (x^2-3x)/(t^2+8) ?
The first derivative of (x^2-3x)/(t^2+8) is (2x-3)/(t^2+8)