What is the sum from n=1 to infinity of (2/3)^{n-1} ?

The sum from n=1 to infinity of (2/3)^{n-1} is converges

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sum from n=1 to infinity of (2/3)^{n-1}

n = 1 \sum \infty (\frac{2}{3})^{n - 1}

converges

Solution steps

n = 1 \sum \infty (\frac{2}{3})^{n - 1}

Apply Series Ratio Test:

converges

= converges

x \to o lim (f (x))

f (x) = x^{3} - 2 x^{2} - 2 x + 1

\int \frac{1}{( x ^{2} + 7 ) ^{\frac{3}{2}}} d x

\frac{d x}{d t} = 0

h \to 0 lim (\frac{7}{3 h})

What is the sum from n=1 to infinity of (2/3)^{n-1} ?
The sum from n=1 to infinity of (2/3)^{n-1} is converges