What is (\partial)/(\partial x)(y^2-2xy) ?

The answer to (\partial)/(\partial x)(y^2-2xy) is -2y

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(\partial)/(\partial x)(y^2-2xy)

\frac{\partial}{\partial x} (y^{2} - 2 x y)

- 2 y

Solution steps

\frac{\partial}{\partial x} (y^{2} - 2 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (2 x y)

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (2 x y) = 2 y

= 0 - 2 y

Simplify

= - 2 y

\frac{d}{d x} (\frac{x}{2})

f (x) = \frac{5}{x}, at x = 4, x = 5

y = (9 x^{2} - 18 x + 18) e^{- 4 x}

\int x^{2} e^{3 x} d x

f (x) = \frac{1}{5 + x ^{2}}, at x = 2

What is (\partial)/(\partial x)(y^2-2xy) ?
The answer to (\partial)/(\partial x)(y^2-2xy) is -2y