What is the derivative of sin(xy)+pi ?

The derivative of sin(xy)+pi is ycos(xy)

What is the first derivative of sin(xy)+pi ?

The first derivative of sin(xy)+pi is ycos(xy)

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derivative of

sin (x y) + π

y cos (x y)

Solution steps

\frac{d}{d x} (sin (x y) + π)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x y)) + \frac{d}{d x} (π)

\frac{d}{d x} (sin (x y)) = cos (x y) y

\frac{d}{d x} (π) = 0

= cos (x y) y + 0

Simplify

= y cos (x y)

\frac{d y}{d x} = \frac{x}{y 1 + x}

\int 3 cos (x) d x

\int \frac{4 x}{x ^{2} + 1} d x

\int e^{3 t} - \frac{1}{2 t} d t

(3.6) (10.12)

What is the derivative of sin(xy)+pi ?
The derivative of sin(xy)+pi is ycos(xy)
What is the first derivative of sin(xy)+pi ?
The first derivative of sin(xy)+pi is ycos(xy)