What is the tangent of f(x)=e^x,\at x=5 ?

The tangent of f(x)=e^x,\at x=5 is y=e^5x-4e^5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=e^x,\at x=5

tangent of

f (x) = e^{x}, at x = 5

y = e^{5} x - 4 e^{5}

Solution steps

Find the tangent point:

(5, e^{5})

Find the slope of

f (x) = e^{x} : \frac{df ( x )}{d x} = e^{x}

Compute the slope of

f (x) = e^{x}

x = 5 : m = e^{5}

Find the line with slope m=

e^{5}

and passing through

(5, e^{5}) : y = e^{5} x - 4 e^{5}

y = e^{5} x - 4 e^{5}

x \to 0 lim (\frac{2}{1 - 2 ^{\frac{1}{x}}})

t^{3} \frac{d y}{d t} + 4 t^{2} y = e^{- t}, y (- 1) = 0

f (x) = \frac{2}{x - 1}

- \frac{5}{s ( 50 + 20 s )}

\frac{d}{d x} (ln (\frac{1 - x ^{2}}{1 + x ^{2}}))

What is the tangent of f(x)=e^x,\at x=5 ?
The tangent of f(x)=e^x,\at x=5 is y=e^5x-4e^5