What is the sum from n=0 to infinity of (x^n)/(3+2x) ?

The sum from n=0 to infinity of (x^n)/(3+2x) is Interval of convergence is-1<x<1

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sum from n=0 to infinity of (x^n)/(3+2x)

n = 0 \sum \infty \frac{x ^{n}}{3 + 2 x}

Interval of convergence is - 1 < x < 1

Solution steps

n = 0 \sum \infty \frac{x ^{n}}{3 + 2 x}

Use the Ratio Test to compute the convergence interval

Interval of convergence is - 1 < x < 1

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What is the sum from n=0 to infinity of (x^n)/(3+2x) ?
The sum from n=0 to infinity of (x^n)/(3+2x) is Interval of convergence is-1<x<1