What is the derivative of-(2x)/((x^2+1)^2) ?

The derivative of-(2x)/((x^2+1)^2) is -(2(-3x^2+1))/((x^2+1)^3)

What is the first derivative of-(2x)/((x^2+1)^2) ?

The first derivative of-(2x)/((x^2+1)^2) is -(2(-3x^2+1))/((x^2+1)^3)

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derivative of

- \frac{2 x}{( x ^{2} + 1 ) ^{2}}

- \frac{2 ( - 3 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{2 x}{( x ^{2} + 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 2 \cdot \frac{\frac{d x}{d x} ( x ^{2} + 1 ) ^{2} - \frac{d}{d x} ( ( x ^{2} + 1 ) ^{2} ) x}{( ( x ^{2} + 1 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} + 1)^{2}) = 4 x (x^{2} + 1)

= - 2 \cdot \frac{1 \cdot ( x ^{2} + 1 ) ^{2} - 4 x ( x ^{2} + 1 ) x}{( ( x ^{2} + 1 ) ^{2} ) ^{2}}

Simplify

- 2 \cdot \frac{1 \cdot ( x ^{2} + 1 ) ^{2} - 4 x ( x ^{2} + 1 ) x}{( ( x ^{2} + 1 ) ^{2} ) ^{2}} : - \frac{2 ( - 3 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{3}}

= - \frac{2 ( - 3 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{3}}

y^{^{''}} + 2 y^{^{'}} + \frac{3}{4} y = \frac{3}{4}

\int x^{3} cos (2 x) d x

\frac{e ^{x} + e ^{- x}}{2}

\int (6 e^{5 x} - \frac{7}{x}) d x

\frac{d}{d x} (\frac{6 x - 3}{x - 3})

What is the derivative of-(2x)/((x^2+1)^2) ?
The derivative of-(2x)/((x^2+1)^2) is -(2(-3x^2+1))/((x^2+1)^3)
What is the first derivative of-(2x)/((x^2+1)^2) ?
The first derivative of-(2x)/((x^2+1)^2) is -(2(-3x^2+1))/((x^2+1)^3)