What is the integral of 1/(sqrt(y)) ?

The integral of 1/(sqrt(y)) is 2sqrt(y)+C

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integral of 1/(sqrt(y))

\int \frac{1}{y} d y

2 y + C

Solution steps

\int \frac{1}{y} d y

Apply the Power Rule

: 2 y^{\frac{1}{2}}

= 2 y^{\frac{1}{2}}

Apply radical rule:

= 2 y

Add a constant to the solution

= 2 y + C

\frac{1}{2 x + 1}

\int_{- π}^{2 π} π cos^{2} (x) d x

f (x) = 3 x^{2} e^{x} + e^{x} (x^{3} + 2)

\int \frac{49 + x ^{2}}{x} d x

x \to 2 + lim (\frac{5 + x}{2 - x})