What is the integral from 0 to x^2 of e^{t^2} ?

The integral from 0 to x^2 of e^{t^2} is (sqrt(pi))/2 \erfi(x^2)

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integral from 0 to x^2 of e^{t^2}

\int_{0}^{x^{2}} e^{t^{2}} d t

\frac{π}{2} erfi (x^{2})

Solution steps

\int_{0}^{x^{2}} e^{t^{2}} d t

Use the nonelementary integral:

\int e^{t^{2}} d t = \frac{π}{2} erfi (t)

= [\frac{π}{2} erfi (t)]_{0}^{x^{2}}

Compute the boundaries:

\frac{π}{2} erfi (x^{2})

= \frac{π}{2} erfi (x^{2})

t \to 2 lim (\frac{t + 2}{t ^{2} - 4})

x \to \infty lim (- 2 x - 1)

f (x) = \frac{2}{x - 8}, at x = 10

\int 22 sec^{4} (θ) tan^{2} (θ) d θ

(4.1) (1.1)

What is the integral from 0 to x^2 of e^{t^2} ?
The integral from 0 to x^2 of e^{t^2} is (sqrt(pi))/2 \erfi(x^2)