What is laplacetransform f(t)=te^t ?

The answer to laplacetransform f(t)=te^t is 1/((s-1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform f(t)=te^t

laplace transform

f (t) = t e^{t}

\frac{1}{( s - 1 ) ^{2}}

Solution steps

L {e^{t} t}

Use Laplace Transform table:

L {t^{k} f (t)} = (- 1)^{k} \frac{d ^{k}}{d s ^{k}} (L {f (t)})

For

t e^{t} : f (t) = e^{t}, k = 1

= (- 1)^{1} \frac{d}{d s} (L {e^{t}})

L {e^{t}} : \frac{1}{s - 1}

\frac{d}{d s} (\frac{1}{s - 1}) = - \frac{1}{( s - 1 ) ^{2}}

= (- 1)^{1} (- \frac{1}{( s - 1 ) ^{2}})

= \frac{1}{( s - 1 ) ^{2}}

f (x) = cos (\frac{π x}{2}), at x = 0.7

x y d x - (x^{2} - x) d y = 0

\frac{\partial}{\partial x} (sin (x y) + cos (x y))

\int 13 cot^{4} (x) d x

\int_{0}^{\frac{7 π}{4}} sec^{4} (\frac{t}{7}) d t

What is laplacetransform f(t)=te^t ?
The answer to laplacetransform f(t)=te^t is 1/((s-1)^2)