What is the integral from 1 to 2 of e^x ?

The integral from 1 to 2 of e^x is e^2-e

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integral from 1 to 2 of e^x

\int_{1}^{2} e^{x} d x

e^{2} - e

Decimal Notation

4.67077 \dots

Solution steps

\int_{1}^{2} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= [e^{x}]_{1}^{2}

Compute the boundaries:

e^{2} - e

= e^{2} - e

\int x e^{- a x} d x

\frac{1}{( 1 + s ^{2} ) ( s ^{2} + 3 )}

\int_{0}^{1} ∣ x ∣ d x

f (x) = x + x, at x = 1

\int_{0}^{1} 2^{- θ} d θ

What is the integral from 1 to 2 of e^x ?
The integral from 1 to 2 of e^x is e^2-e