What is inverse oflaplace 3x+2 ?

The answer to inverse oflaplace 3x+2 is 3\delta'(t)+2\delta(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace 3x+2

inverse laplace

3 x + 2

3 δ' (t) + 2 δ (t)

Solution steps

L^{- 1} {3 x + 2}

Use the linearity property of Inverse Laplace Transform:

For functions

f (s), g (s)

and constants

a, b : L^{- 1} {a \cdot f (s) + b \cdot g (s)} = a \cdot L^{- 1} {f (s)} + b \cdot L^{- 1} {g (s)}

= 3 L^{- 1} {x} + L^{- 1} {2}

L^{- 1} {x} : δ^{'} (t)

L^{- 1} {2} : 2 δ (t)

= 3 δ^{^{'}} (t) + 2 δ (t)

\int cos^{4} (x s i) n^{2} x d x

\int \frac{x}{( 4 x ^{2} + 3 ) ^{6}} d x

e^{- t} (t^{2} + 1)

\frac{3}{2 3 x + 7}, at x = 6

\frac{d}{d x} (x^{2} arctan (x))

What is inverse oflaplace 3x+2 ?
The answer to inverse oflaplace 3x+2 is 3\delta'(t)+2\delta(t)