What is the derivative of 1/2 x^4+11x^3+30x^2 ?

The derivative of 1/2 x^4+11x^3+30x^2 is 2x^3+33x^2+60x

What is the first derivative of 1/2 x^4+11x^3+30x^2 ?

The first derivative of 1/2 x^4+11x^3+30x^2 is 2x^3+33x^2+60x

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derivative of

\frac{1}{2} x^{4} + 11 x^{3} + 30 x^{2}

2 x^{3} + 33 x^{2} + 60 x

Solution steps

\frac{d}{d x} (\frac{1}{2} x^{4} + 11 x^{3} + 30 x^{2})

Simplify

\frac{1}{2} x^{4} + 11 x^{3} + 30 x^{2} : \frac{x ^{4}}{2} + 11 x^{3} + 30 x^{2}

= \frac{d}{d x} (\frac{x ^{4}}{2} + 11 x^{3} + 30 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{2}) + \frac{d}{d x} (11 x^{3}) + \frac{d}{d x} (30 x^{2})

\frac{d}{d x} (\frac{x ^{4}}{2}) = 2 x^{3}

\frac{d}{d x} (11 x^{3}) = 33 x^{2}

\frac{d}{d x} (30 x^{2}) = 60 x

= 2 x^{3} + 33 x^{2} + 60 x

\frac{2 d y}{d x} + 5 y = 4

x \to 0 lim (\frac{1}{3})

x \to 0 lim (f (x) x)

4 x y^{^{'}} - (1 + x) y = 2 x y^{2}

\frac{d y}{d x} = \frac{( y ^{3} + x ^{3} )}{x y ^{2}}

What is the derivative of 1/2 x^4+11x^3+30x^2 ?
The derivative of 1/2 x^4+11x^3+30x^2 is 2x^3+33x^2+60x
What is the first derivative of 1/2 x^4+11x^3+30x^2 ?
The first derivative of 1/2 x^4+11x^3+30x^2 is 2x^3+33x^2+60x