What is (16)/((5-x)^2)-1 ?

The solution to (16)/((5-x)^2)-1 is (-x^2+10x-9)/((5-x)^2)

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simplify (16)/((5-x)^2)-1

simplify

\frac{16}{( 5 - x ) ^{2}} - 1

\frac{- x ^{2} + 10 x - 9}{( 5 - x ) ^{2}}

Solution steps

\frac{16}{( 5 - x ) ^{2}} - 1

Apply the fraction rule:

a + \frac{b}{c} = \frac{a c + b}{c}

= \frac{- 1 \cdot ( 5 - x ) ^{2} + 16}{( 5 - x ) ^{2}}

Apply rule:

1 \cdot a = a

- 1 \cdot (5 - x)^{2} = - (5 - x)^{2}

= \frac{- ( 5 - x ) ^{2} + 16}{( 5 - x ) ^{2}}

Simplify

- (5 - x)^{2} + 16 : - x^{2} + 10 x - 9

= \frac{- x ^{2} + 10 x - 9}{( 5 - x ) ^{2}}

\frac{\partial}{\partial x} (arcsin (3 x - 2))

f (x) = \frac{x}{x ^{2} - 16}

x \to 1 lim (\frac{x}{1 - x ^{4}})

y = \frac{40}{x}, y = - 9 x + 39

\frac{d}{d x} (6 x - 2 x)

What is (16)/((5-x)^2)-1 ?
The solution to (16)/((5-x)^2)-1 is (-x^2+10x-9)/((5-x)^2)