What is inverse oflaplace 1/(15s^3) ?

The answer to inverse oflaplace 1/(15s^3) is (t^2)/(30)

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inverse oflaplace 1/(15s^3)

inverse laplace

\frac{1}{15 s ^{3}}

\frac{t ^{2}}{30}

Solution steps

L^{- 1} {\frac{1}{15 s ^{3}}}

= L^{- 1} {\frac{1}{30} \cdot \frac{2}{s ^{3}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{30} L^{- 1} {\frac{2}{s ^{3}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{2}{s ^{3}}} = t^{2}

= \frac{1}{30} t^{2}

= \frac{t ^{2}}{30}

\frac{\partial}{\partial x} ((x - cy)^{9} + (x + cy)^{9})

\frac{x ^{2}}{x + 5}

\int_{- 5}^{6} 0

\frac{d}{d x} (- 6 sin (x) - 6 x cos (x) + x^{2} sin (x))

y = x^{8} f (x)

What is inverse oflaplace 1/(15s^3) ?
The answer to inverse oflaplace 1/(15s^3) is (t^2)/(30)