What is the tangent of f(x)=sqrt(4x+84),(4,10) ?

The tangent of f(x)=sqrt(4x+84),(4,10) is y= 1/5 x+46/5

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tangent of f(x)=sqrt(4x+84),(4,10)

tangent of

f (x) = 4 x + 84, (4, 10)

y = \frac{1}{5} x + \frac{46}{5}

Solution steps

Find the slope of

f (x) = 4 x + 84 : \frac{df ( x )}{d x} = \frac{1}{x + 21}

Compute the slope of

f (x) = 4 x + 84

(4, 10) : m = \frac{1}{5}

Find the line with slope m=

\frac{1}{5}

and passing through

(4, 10) : y = \frac{1}{5} x + \frac{46}{5}

y = \frac{1}{5} x + \frac{46}{5}

\frac{d ^{2}}{d x ^{2}} (2^{(x^{2} + 1)})

\int_{0}^{x^{2}} sin (t^{3}) d t

\frac{d}{d x} (cos (a^{3} + x^{3}))

\int sec (3 t) d t

x \to \frac{π}{2} - lim (x sec (x))

What is the tangent of f(x)=sqrt(4x+84),(4,10) ?
The tangent of f(x)=sqrt(4x+84),(4,10) is y= 1/5 x+46/5