What is the derivative of x^{1/2}+4x^{2/3}+7x+3 ?

The derivative of x^{1/2}+4x^{2/3}+7x+3 is 1/(2x^{1/2)}+8/(3x^{1/3)}+7

What is the first derivative of x^{1/2}+4x^{2/3}+7x+3 ?

The first derivative of x^{1/2}+4x^{2/3}+7x+3 is 1/(2x^{1/2)}+8/(3x^{1/3)}+7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{\frac{1}{2}} + 4 x^{\frac{2}{3}} + 7 x + 3)

\frac{1}{2 x ^{\frac{1}{2}}} + \frac{8}{3 x ^{\frac{1}{3}}} + 7

Solution steps

\frac{d}{d x} (x^{\frac{1}{2}} + 4 x^{\frac{2}{3}} + 7 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{\frac{1}{2}}) + \frac{d}{d x} (4 x^{\frac{2}{3}}) + \frac{d}{d x} (7 x) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{\frac{1}{2}}) = \frac{1}{2 x ^{\frac{1}{2}}}

\frac{d}{d x} (4 x^{\frac{2}{3}}) = \frac{8}{3 x ^{\frac{1}{3}}}

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (3) = 0

= \frac{1}{2 x ^{\frac{1}{2}}} + \frac{8}{3 x ^{\frac{1}{3}}} + 7 + 0

Simplify

= \frac{1}{2 x ^{\frac{1}{2}}} + \frac{8}{3 x ^{\frac{1}{3}}} + 7

\frac{\partial}{\partial x} (x (7 - x - y))

x \to 0 lim (cot (7 x))

\int 9 tan (9 x) d x

x \to 5 lim (4 x)

\int (3 x + 2 y) d x

What is the derivative of x^{1/2}+4x^{2/3}+7x+3 ?
The derivative of x^{1/2}+4x^{2/3}+7x+3 is 1/(2x^{1/2)}+8/(3x^{1/3)}+7
What is the first derivative of x^{1/2}+4x^{2/3}+7x+3 ?
The first derivative of x^{1/2}+4x^{2/3}+7x+3 is 1/(2x^{1/2)}+8/(3x^{1/3)}+7