What is the derivative of 5t^{7/5}+5e^3 ?

The derivative of 5t^{7/5}+5e^3 is 7t^{2/5}

What is the first derivative of 5t^{7/5}+5e^3 ?

The first derivative of 5t^{7/5}+5e^3 is 7t^{2/5}

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derivative of

5 t^{\frac{7}{5}} + 5 e^{3}

7 t^{\frac{2}{5}}

Solution steps

\frac{d}{d t} (5 t^{\frac{7}{5}} + 5 e^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (5 t^{\frac{7}{5}}) + \frac{d}{d t} (5 e^{3})

\frac{d}{d t} (5 t^{\frac{7}{5}}) = 7 t^{\frac{2}{5}}

\frac{d}{d t} (5 e^{3}) = 0

= 7 t^{\frac{2}{5}} + 0

Simplify

= 7 t^{\frac{2}{5}}

y^{^{'}} = 7 y^{2} sin (x)

\frac{d}{d m} (5 m^{2} + 15 m^{3})

\int \frac{x}{x ^{2} + a ^{2}} d x

\int 34 x + 20 \cdot (- \frac{1}{10}) x + 1 d x

\int \frac{1}{9 e ^{- 5 x} + e ^{5 x}} d x

What is the derivative of 5t^{7/5}+5e^3 ?
The derivative of 5t^{7/5}+5e^3 is 7t^{2/5}
What is the first derivative of 5t^{7/5}+5e^3 ?
The first derivative of 5t^{7/5}+5e^3 is 7t^{2/5}