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Popular >

y^'=2y^2+xy^2

Solution

y^{^{'}} = 2 y^{2} + x y^{2}

Solution

y = - \frac{2}{4 x + x ^{2} + c _{1}}

Solution steps

y^{'} (x) = 2 y^{2} + x y^{2}

Solve separable ODE:

y = - \frac{2}{4 x + x ^{2} + c _{1}}

y = - \frac{2}{4 x + x ^{2} + c _{1}}

Popular Examples

11y^{''}+13y^'+13/44 y=0,y(0)=2,y^'(0)=1

11 y^{^{''}} + 13 y^{^{'}} + \frac{13}{44} y = 0, y (0) = 2, y^{^{'}} (0) = 1

derivative of (sec(2x)/(1+tan(2x)))

\frac{d}{d x} (\frac{sec ( 2 x )}{1 + tan ( 2 x )})

derivative of x^{2/x}derivative of

x^{\frac{2}{x}}

limit as x approaches 0 of (5x+x^2)/x

x \to 0 lim (\frac{5 x + x ^{2}}{x})

integral of cot^3(x/3)

\int cot^{3} (\frac{x}{3}) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=2y^2+xy^2 ?
The solution for y^'=2y^2+xy^2 is y=-2/(4x+x^2+c_{1)}