What is the solution for (dy)/(dx)+3tan(3x)y=-5cos(3x) ?

The solution for (dy)/(dx)+3tan(3x)y=-5cos(3x) is y=-(5x)/(sec(3x))+(c_{1})/(sec(3x))

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(dy)/(dx)+3tan(3x)y=-5cos(3x)

\frac{d y}{d x} + 3 tan (3 x) y = - 5 cos (3 x)

y = - \frac{5 x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

Solution steps

\frac{d y}{d x} + 3 tan (3 x) y = - 5 cos (3 x)

Solve linear ODE:

y = - \frac{5 x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

y = - \frac{5 x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

x \to 0 lim (x)

n = 0 \sum \infty \frac{- 1 ^{n}}{n + 2}

\frac{d h}{d t} = - h^{2}

\int \frac{4}{x ^{4} - x ^{2}} d x

\int \frac{1}{x ^{2} x ^{2} - 5} d x

What is the solution for (dy)/(dx)+3tan(3x)y=-5cos(3x) ?
The solution for (dy)/(dx)+3tan(3x)y=-5cos(3x) is y=-(5x)/(sec(3x))+(c_{1})/(sec(3x))