What is the derivative of ln(3+x^2) ?

The derivative of ln(3+x^2) is (2x)/(3+x^2)

What is the first derivative of ln(3+x^2) ?

The first derivative of ln(3+x^2) is (2x)/(3+x^2)

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\frac{d}{d x} (ln (3 + x^{2}))

\frac{2 x}{3 + x ^{2}}

Solution steps

\frac{d}{d x} (ln (3 + x^{2}))

Apply the chain rule:

\frac{1}{3 + x ^{2}} \frac{d}{d x} (3 + x^{2})

= \frac{1}{3 + x ^{2}} \frac{d}{d x} (3 + x^{2})

\frac{d}{d x} (3 + x^{2}) = 2 x

= \frac{1}{3 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{3 + x ^{2}} \cdot 2 x : \frac{2 x}{3 + x ^{2}}

= \frac{2 x}{3 + x ^{2}}

x^{^{'}} + 6 x = 0

n = 0 \sum \infty 3 \cdot (- \frac{2}{5})^{n}

f (x) = \frac{2 x}{x - 1}, at x = 2

\int (x^{2} + 1) e^{2 x} d x

f (x) = 5 e^{x}

What is the derivative of ln(3+x^2) ?
The derivative of ln(3+x^2) is (2x)/(3+x^2)
What is the first derivative of ln(3+x^2) ?
The first derivative of ln(3+x^2) is (2x)/(3+x^2)