What is the derivative of tan(t)-e^{-t} ?

The derivative of tan(t)-e^{-t} is sec^2(t)+e^{-t}

What is the first derivative of tan(t)-e^{-t} ?

The first derivative of tan(t)-e^{-t} is sec^2(t)+e^{-t}

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derivative of

tan (t) - e^{- t}

sec^{2} (t) + e^{- t}

Solution steps

\frac{d}{d t} (tan (t) - e^{- t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (tan (t)) - \frac{d}{d t} (e^{- t})

\frac{d}{d t} (tan (t)) = sec^{2} (t)

\frac{d}{d t} (e^{- t}) = - e^{- t}

= sec^{2} (t) - (- e^{- t})

Simplify

= sec^{2} (t) + e^{- t}

\int \frac{cos ( x )}{sin ^{3} ( x ) - 4 sin ( x )} d x

\int (csc^{2} (θ) + 9) d θ

f (x) = cos (x), 0, \frac{π}{4}

f (x) = \frac{x ^{3}}{2} - \frac{4}{3 x}, at x = 2

y = e^{m x} m

What is the derivative of tan(t)-e^{-t} ?
The derivative of tan(t)-e^{-t} is sec^2(t)+e^{-t}
What is the first derivative of tan(t)-e^{-t} ?
The first derivative of tan(t)-e^{-t} is sec^2(t)+e^{-t}