Solution
Solution
Solution steps
Apply the chain rule:
Simplify
Popular Examples
y^'=(sec(y))/((x+2)^2)tangent of f(x)=-3+(x+4)^2,\at x=-5tangent of inverse oflaplace (2*(s^2+1))/(s^4)inverse laplace derivative of e^{(x^2/(2a)})y^'=y^2-8
Frequently Asked Questions (FAQ)
What is the derivative of arcsec(e^{3x}) ?
The derivative of arcsec(e^{3x}) is 3/(sqrt(e^{6x)-1)}What is the first derivative of arcsec(e^{3x}) ?
The first derivative of arcsec(e^{3x}) is 3/(sqrt(e^{6x)-1)}