What is the slope of x^4-8x^2+16 ?

The slope of x^4-8x^2+16 is 4x^3-16x

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slope of x^4-8x^2+16

slope

x^{4} - 8 x^{2} + 16

4 x^{3} - 16 x

Solution steps

y = x^{4} - 8 x^{2} + 16

In order to find the slope of the function, take the derivative of

x^{4} - 8 x^{2} + 16

\frac{d}{d x} (x^{4} - 8 x^{2} + 16) = 4 x^{3} - 16 x

4 x^{3} - 16 x

\frac{d}{d x} (\frac{- 3}{x - 6} - 2)

\frac{d}{d x} (0.8 \cdot x^{4})

\int x sin^{2} (x) cos^{3} (x) d x

\int (4 x^{2} + 8 x + 5)^{6} (x + 1) d x