What is (\partial)/(\partial u)(tan(u/v)) ?

The answer to (\partial)/(\partial u)(tan(u/v)) is (sec^2(u/v))/v

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial u)(tan(u/v))

\frac{\partial}{\partial u} (tan (\frac{u}{v}))

\frac{sec ^{2} ( \frac{u}{v} )}{v}

Solution steps

\frac{\partial}{\partial u} (tan (\frac{u}{v}))

Treat

v

as a constant

Apply the chain rule:

sec^{2} (\frac{u}{v}) \frac{\partial}{\partial u} (\frac{u}{v})

= sec^{2} (\frac{u}{v}) \frac{\partial}{\partial u} (\frac{u}{v})

\frac{\partial}{\partial u} (\frac{u}{v}) = \frac{1}{v}

= sec^{2} (\frac{u}{v}) \frac{1}{v}

Simplify

sec^{2} (\frac{u}{v}) \frac{1}{v} : \frac{sec ^{2} ( \frac{u}{v} )}{v}

= \frac{sec ^{2} ( \frac{u}{v} )}{v}

\int \frac{5 x - 2}{x ^{2} - x} d x

y = x^{2}, y = 12 - x

\frac{d}{d x} (x + 13)

x \to \infty lim (ln ∣ x ∣)

y^{^{''}} + 81 y = 0, y (0) = 4, y^{^{'}} (0) = 7

What is (\partial)/(\partial u)(tan(u/v)) ?
The answer to (\partial)/(\partial u)(tan(u/v)) is (sec^2(u/v))/v