What is the limit as x approaches infinity of xe^{-1} ?

The limit as x approaches infinity of xe^{-1} is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches infinity of xe^{-1}

x \to \infty lim (x e^{- 1})

\infty

Solution steps

x \to \infty lim (x e^{- 1})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= e^{- 1} \cdot x \to \infty lim (x)

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{e} \cdot x \to \infty lim (x)

Apply the common limit:

x \to \infty lim (x) = \infty

= \frac{1}{e} \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

\frac{\partial}{\partial x} (\frac{x}{1 + x ^{2}})

(x^{2} + 1) \frac{d y}{d x} + x y = 4 1 + x^{2}

4 x^{2} - x^{3}

\int_{- \infty}^{0} \frac{1}{5 - 10 x} d x

\int \frac{π}{2}

What is the limit as x approaches infinity of xe^{-1} ?
The limit as x approaches infinity of xe^{-1} is infinity