What is implicit (dy)/(dx), y/x =0 ?

The answer to implicit (dy)/(dx), y/x =0 is (dy)/(dx)= y/x

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implicit (dy)/(dx), y/x =0

implicit derivative

\frac{d y}{d x}, \frac{y}{x} = 0

\frac{d y}{d x} = \frac{y}{x}

Solution steps

\frac{y}{x} = 0

Treat

y

y (x)

Differentiate both sides:

\frac{x \frac{d y}{d x} - y}{x ^{2}} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{y}{x}

\frac{d y}{d x} = \frac{y}{x}

\frac{\partial}{\partial x} (sin (h) (x^{2} + y))

\frac{d}{d x} (- ln (x^{2} + y))

x \to 7 lim (x)

\frac{1}{s ^{2} + s + 1}

\int cos (x) (sec (x) tan (x)) d x

What is implicit (dy)/(dx), y/x =0 ?
The answer to implicit (dy)/(dx), y/x =0 is (dy)/(dx)= y/x