What is (\partial)/(\partial x)(cos(2x+5y+9z)) ?

The answer to (\partial)/(\partial x)(cos(2x+5y+9z)) is -sin(2x+5y+9z)*2

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(\partial)/(\partial x)(cos(2x+5y+9z))

\frac{\partial}{\partial x} (cos (2 x + 5 y + 9 z))

- sin (2 x + 5 y + 9 z) \cdot 2

Solution steps

\frac{\partial}{\partial x} (cos (2 x + 5 y + 9 z))

Treat

y, z

as constants

Apply the chain rule:

- sin (2 x + 5 y + 9 z) \frac{\partial}{\partial x} (2 x + 5 y + 9 z)

= - sin (2 x + 5 y + 9 z) \frac{\partial}{\partial x} (2 x + 5 y + 9 z)

\frac{\partial}{\partial x} (2 x + 5 y + 9 z) = 2

= - sin (2 x + 5 y + 9 z) \cdot 2

f (x) = - sin (x), at x = 0

e^{x + y} y^{^{'}} = x

x \to 5 + lim (ln (sin (x)))

y^{^{'}} = \frac{( x y + 2 y )}{x + 3}

\frac{2 x + x ^{2}}{( 1 + x ) ^{2}}

What is (\partial)/(\partial x)(cos(2x+5y+9z)) ?
The answer to (\partial)/(\partial x)(cos(2x+5y+9z)) is -sin(2x+5y+9z)*2