What is area x^2+2x+1,2x+5,[-2,2] ?

The answer to area x^2+2x+1,2x+5,[-2,2] is 32/3

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area x^2+2x+1,2x+5,[-2,2]

area

x^{2} + 2 x + 1, 2 x + 5, [- 2, 2]

\frac{32}{3}

Decimal

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} + 2 x + 1 - (2 x + 5) d x

Solve

\int_{- 2}^{2} x^{2} + 2 x + 1 - (2 x + 5) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

\int_{0}^{π} sin (3 x) d x

\frac{d y}{d x} = y^{2} sin (x^{2}), y (- 5) = \frac{1}{7}

\frac{d}{d x} ((x - π) sin (y) + sin (x) cos (y))

f (x) = 2 lo g_{5} (x)

\int \frac{8}{2 + 8 x} d x

What is area x^2+2x+1,2x+5,[-2,2] ?
The answer to area x^2+2x+1,2x+5,[-2,2] is 32/3