What is the derivative of g(x)=sqrt(-x) ?

The derivative of g(x)=sqrt(-x) is -1/(2sqrt(-x))

What is the first derivative of g(x)=sqrt(-x) ?

The first derivative of g(x)=sqrt(-x) is -1/(2sqrt(-x))

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derivative of

g (x) = - x

- \frac{1}{2 - x}

Solution steps

\frac{d}{d x} (- x)

Apply the chain rule:

\frac{1}{2 - x} \frac{d}{d x} (- x)

= \frac{1}{2 - x} \frac{d}{d x} (- x)

\frac{d}{d x} (- x) = - 1

= \frac{1}{2 - x} (- 1)

Simplify

= - \frac{1}{2 - x}

\frac{d y}{d x} = 2 y - x y^{2}

\int - \frac{5}{12 - 12 x ^{2}} d x

\frac{d}{d x} (\frac{x ^{2} + 5}{x ^{2} + 6 x})

y = x^{2} - 2 x - 3, (2, - 3)

n = 0 \sum \infty c n (x - 8)^{n}

What is the derivative of g(x)=sqrt(-x) ?
The derivative of g(x)=sqrt(-x) is -1/(2sqrt(-x))
What is the first derivative of g(x)=sqrt(-x) ?
The first derivative of g(x)=sqrt(-x) is -1/(2sqrt(-x))