What is the derivative of 2x^3-6 ?

The derivative of 2x^3-6 is 6x^2

What is the first derivative of 2x^3-6 ?

The first derivative of 2x^3-6 is 6x^2

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\frac{d}{d x} (2 x^{3} - 6)

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (6)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (6) = 0

= 6 x^{2} - 0

Simplify

= 6 x^{2}

\frac{d}{d x} (24 x + sin (x))

f (x) = arcsin (2 x)

\frac{d}{d x} (\frac{arccos ( x )}{x ^{2}})

\int_{1}^{2} x^{2} - 3 x + 2 d x