What is the integral of 3/4 sec(x)tan(x) ?

The integral of 3/4 sec(x)tan(x) is 3/4 sec(x)+C

Popular >

integral of 3/4 sec(x)tan(x)

\int \frac{3}{4} sec (x) tan (x) d x

\frac{3}{4} sec (x) + C

Solution steps

\int \frac{3}{4} sec (x) tan (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{4} \cdot \int sec (x) tan (x) d x

Apply u-substitution

: \int 1 d u

= \frac{3}{4} \cdot \int 1 d u

Integral of a constant:

\int a d x = a x

= \frac{3}{4} \cdot 1 \cdot u

Substitute back

u = sec (x)

= \frac{3}{4} \cdot 1 \cdot sec (x)

Simplify

= \frac{3}{4} sec (x)

Add a constant to the solution

= \frac{3}{4} sec (x) + C

tan (2 x + 3)

x \to 0 lim (3 - 7 x - 5 x^{2})

2 x + 3 y + 4 = 0, [- 4, 4]

\int \frac{sec ^{2} ( x )}{tan ( x )} d x

y = x^{2} - 8 x, (5, - 15)

What is the integral of 3/4 sec(x)tan(x) ?
The integral of 3/4 sec(x)tan(x) is 3/4 sec(x)+C