What is the derivative of 2x^2-3x-5 ?

The derivative of 2x^2-3x-5 is 4x-3

What is the first derivative of 2x^2-3x-5 ?

The first derivative of 2x^2-3x-5 is 4x-3

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\frac{d}{d x} (2 x^{2} - 3 x - 5)

4 x - 3

Solution steps

\frac{d}{d x} (2 x^{2} - 3 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3 x) - \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 4 x - 3 - 0

Simplify

= 4 x - 3

\frac{d}{d x} (ln (a x))

\int \frac{3}{y ^{π}} d y

\frac{\partial}{\partial x} (\frac{8.31 y}{x})

\frac{\partial}{\partial x} (x cos (y) - 2 y)

\int (x^{2} \frac{e ^{- 2 x}}{2}) d x

What is the derivative of 2x^2-3x-5 ?
The derivative of 2x^2-3x-5 is 4x-3
What is the first derivative of 2x^2-3x-5 ?
The first derivative of 2x^2-3x-5 is 4x-3