What is the derivative of b/a sqrt(a^2-x^2) ?

The derivative of b/a sqrt(a^2-x^2) is -(bx)/(asqrt(a^2-x^2))

What is the first derivative of b/a sqrt(a^2-x^2) ?

The first derivative of b/a sqrt(a^2-x^2) is -(bx)/(asqrt(a^2-x^2))

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Popular >

\frac{d}{d x} (\frac{b}{a} a^{2} - x^{2})

- \frac{b x}{a a ^{2} - x ^{2}}

Solution steps

\frac{d}{d x} (\frac{b}{a} a^{2} - x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{b}{a} \frac{d}{d x} (a^{2} - x^{2})

Apply the chain rule:

\frac{1}{2 a ^{2} - x ^{2}} \frac{d}{d x} (a^{2} - x^{2})

= \frac{1}{2 a ^{2} - x ^{2}} \frac{d}{d x} (a^{2} - x^{2})

\frac{d}{d x} (a^{2} - x^{2}) = - 2 x

= \frac{b}{a} \cdot \frac{1}{2 a ^{2} - x ^{2}} (- 2 x)

Simplify

\frac{b}{a} \cdot \frac{1}{2 a ^{2} - x ^{2}} (- 2 x) : - \frac{b x}{a a ^{2} - x ^{2}}

= - \frac{b x}{a a ^{2} - x ^{2}}

\frac{\partial}{\partial T} (\frac{x}{T})

5 \cdot 3^{x}

\int_{0}^{1} 4 cos (x^{2}) d x

\int_{- 20}^{0} \frac{1}{16 - x} d x

\frac{e ^{- 2 s}}{( s ^{2} + 16 )}

What is the derivative of b/a sqrt(a^2-x^2) ?
The derivative of b/a sqrt(a^2-x^2) is -(bx)/(asqrt(a^2-x^2))
What is the first derivative of b/a sqrt(a^2-x^2) ?
The first derivative of b/a sqrt(a^2-x^2) is -(bx)/(asqrt(a^2-x^2))