What is the solution for (dy)/(dx)=(x-4)/(y-6) ?

The solution for (dy)/(dx)=(x-4)/(y-6) is y=6+sqrt(x^2-8x+c_{1)+36},y=6-sqrt(x^2-8x+c_{1)+36}

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(dy)/(dx)=(x-4)/(y-6)

\frac{d y}{d x} = \frac{x - 4}{y - 6}

y = 6 + x^{2} - 8 x + c_{1} + 36, y = 6 - x^{2} - 8 x + c_{1} + 36

Solution steps

\frac{d y}{d x} = \frac{x - 4}{y - 6}

Solve separable ODE:

y = 6 + x^{2} - 8 x + c_{1} + 36, y = 6 - x^{2} - 8 x + c_{1} + 36

y = 6 + x^{2} - 8 x + c_{1} + 36, y = 6 - x^{2} - 8 x + c_{1} + 36

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\int_{0}^{1} (5^{x} - 3^{x}) d x

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What is the solution for (dy)/(dx)=(x-4)/(y-6) ?
The solution for (dy)/(dx)=(x-4)/(y-6) is y=6+sqrt(x^2-8x+c_{1)+36},y=6-sqrt(x^2-8x+c_{1)+36}