What is the tangent of f(x)=9e^x,\at x=7 ?

The tangent of f(x)=9e^x,\at x=7 is y=9e^7x-54e^7

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tangent of f(x)=9e^x,\at x=7

tangent of

f (x) = 9 e^{x}, at x = 7

y = 9 e^{7} x - 54 e^{7}

Solution steps

Find the tangent point:

(7, 9 e^{7})

Find the slope of

f (x) = 9 e^{x} : \frac{df ( x )}{d x} = 9 e^{x}

Compute the slope of

f (x) = 9 e^{x}

x = 7 : m = 9 e^{7}

Find the line with slope m=

9 e^{7}

and passing through

(7, 9 e^{7}) : y = 9 e^{7} x - 54 e^{7}

y = 9 e^{7} x - 54 e^{7}

\int_{1}^{12} \frac{1}{x - 7} d x

\frac{\partial}{\partial y} (x^{2} + 6 x y + 4 y^{2})

\int x^{2} + 2 x + 1 d x

\frac{x ^{2} - 1}{2 x - 3}

\int_{0}^{1} \frac{2 y}{e ^{2 y}} d y

What is the tangent of f(x)=9e^x,\at x=7 ?
The tangent of f(x)=9e^x,\at x=7 is y=9e^7x-54e^7