What is the integral of 10+6x+36x^2 ?

The integral of 10+6x+36x^2 is 10x+3x^2+12x^3+C

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integral of 10+6x+36x^2

\int 10 + 6 x + 36 x^{2} d x

10 x + 3 x^{2} + 12 x^{3} + C

Solution steps

\int 10 + 6 x + 36 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 10 d x + \int 6 x d x + \int 36 x^{2} d x

\int 10 d x = 10 x

\int 6 x d x = 3 x^{2}

\int 36 x^{2} d x = 12 x^{3}

= 10 x + 3 x^{2} + 12 x^{3}

Add a constant to the solution

= 10 x + 3 x^{2} + 12 x^{3} + C

\int 1 - \frac{x ^{2}}{16} d x

y x \frac{d y}{d x} = \frac{sec ( 3 y )}{1 + x}

\int \frac{5 e ^{3 x}}{1 + e ^{2 x}} d x

n = 4 \sum \infty \frac{1}{( n ( n + 1 ) )}

\frac{d}{d x} (\frac{4 x}{( x ^{2} + 1 )})

What is the integral of 10+6x+36x^2 ?
The integral of 10+6x+36x^2 is 10x+3x^2+12x^3+C