What is the derivative of 7/5 sin^2(2x) ?

The derivative of 7/5 sin^2(2x) is 28/5 sin(2x)cos(2x)

What is the first derivative of 7/5 sin^2(2x) ?

The first derivative of 7/5 sin^2(2x) is 28/5 sin(2x)cos(2x)

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\frac{d}{d x} (\frac{7}{5} sin^{2} (2 x))

\frac{28}{5} sin (2 x) cos (2 x)

Solution steps

\frac{d}{d x} (\frac{7}{5} sin^{2} (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{7}{5} \frac{d}{d x} (sin^{2} (2 x))

Apply the chain rule:

2 sin (2 x) \frac{d}{d x} (sin (2 x))

= 2 sin (2 x) \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= \frac{7}{5} \cdot 2 sin (2 x) cos (2 x) \cdot 2

Simplify

\frac{7}{5} \cdot 2 sin (2 x) cos (2 x) \cdot 2 : \frac{28}{5} sin (2 x) cos (2 x)

= \frac{28}{5} sin (2 x) cos (2 x)

\int sec^{2} (2 x - 1) d x

y (x - y - 2) d x + x (y - x + 4) d y = 0

e^{2} y \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

(- 4, 7), (- 6, - 4)

\frac{d}{d x} (ln (cos (sin (e^{x^{3}}))))

What is the derivative of 7/5 sin^2(2x) ?
The derivative of 7/5 sin^2(2x) is 28/5 sin(2x)cos(2x)
What is the first derivative of 7/5 sin^2(2x) ?
The first derivative of 7/5 sin^2(2x) is 28/5 sin(2x)cos(2x)