What is the solution for e^{(x+y)}(dx+dy)+4xdx=0 ?

The solution for e^{(x+y)}(dx+dy)+4xdx=0 is y=ln(-4(-xe^{-x}-e^{-x})+c_{1})

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e^{(x+y)}(dx+dy)+4xdx=0

e^{(x + y)} (d x + d y) + 4 x d x = 0

y = ln (- 4 (- x e^{- x} - e^{- x}) + c_{1})

Solution steps

e^{(x + y)} (d x + d y) + 4 x d x = 0

Solve separable ODE:

y = ln (- 4 (- x e^{- x} - e^{- x}) + c_{1})

y = ln (- 4 (- x e^{- x} - e^{- x}) + c_{1})

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What is the solution for e^{(x+y)}(dx+dy)+4xdx=0 ?
The solution for e^{(x+y)}(dx+dy)+4xdx=0 is y=ln(-4(-xe^{-x}-e^{-x})+c_{1})