What is the integral of sqrt(-x+8) ?

The integral of sqrt(-x+8) is -2/3 (-x+8)^{3/2}+C

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integral of sqrt(-x+8)

\int - x + 8 d x

- \frac{2}{3} (- x + 8)^{\frac{3}{2}} + C

Solution steps

\int - x + 8 d x

Apply u-substitution

: \int - u d u

= \int - u d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= - \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = - x + 8

= - \frac{2}{3} (- x + 8)^{\frac{3}{2}}

Add a constant to the solution

= - \frac{2}{3} (- x + 8)^{\frac{3}{2}} + C

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What is the integral of sqrt(-x+8) ?
The integral of sqrt(-x+8) is -2/3 (-x+8)^{3/2}+C